Tuesday, 18 February 2014

C graphics program moving car

3. C graphics program moving car

#include <graphics.h>
#include <dos.h>
 
int main()
{
   int i, j = 0, gd = DETECT, gm;
 
   initgraph(&gd,&gm,"C:\\TC\\BGI");
 
   settextstyle(DEFAULT_FONT,HORIZ_DIR,2);
   outtextxy(25,240,"Press any key to view the moving car");
 
   getch();
 
   for( i = 0 ; i <= 420 ; i = i + 10, j++ )
   {
      rectangle(50+i,275,150+i,400);
      rectangle(150+i,350,200+i,400);
      circle(75+i,410,10);
      circle(175+i,410,10);
      setcolor(j);
      delay(100);
 
      if( i == 420 )
         break;
      if ( j == 15 )
         j = 2;
 
      cleardevice(); // clear screen
   }
 
   getch();
   closegraph();
   return 0;
}

Declaration :- void circle(int x, int y, int radius);

Declaration :- void circle(int x, int y, int radius);
Circle function is used to draw a circle with center (x,y) and third parameter specifies the radius of the circle. The code given below draws a circle.

C program for circle

#include<graphics.h>
#include<conio.h>
 
main()
{
   int gd = DETECT, gm;
 
   initgraph(&gd, &gm, "C:\\TC\\BGI");
 
   circle(100, 100, 50);
 
   getch();
   closegraph();
   return 0;
}
In the above program (100, 100) are coordinates of center of the circle and 50 is the radius of circle.

Palindrome number program c

Palindrome number algorithm

1. Get the number from user.
2. Reverse it.
3. Compare it with the number entered by the user.
4. If both are same then print palindrome number
5. Else print not a palindrome number.

Palindrome number program c

#include <stdio.h>
 
int main()
{
   int n, reverse = 0, temp;
 
   printf("Enter a number to check if it is a palindrome or not\n");
   scanf("%d",&n);
 
   temp = n;
 
   while( temp != 0 )
   {
      reverse = reverse * 10;
      reverse = reverse + temp%10;
      temp = temp/10;
   }
 
   if ( n == reverse )
      printf("%d is a palindrome number.\n", n);
   else
      printf("%d is not a palindrome number.\n", n);
 
   return 0;
}
Download Palindrome number program.
Output of program:
Palindrome number c prorgram

C hello world program

C programming codes


Example 1 - C hello world program
/* A very simple c program printing a string on screen*/
#include <stdio.h>
 
main()
{
    printf("Hello World\n");
    return 0;
}
Output of above program:
"Hello World"

Example 2 - c program to take input from user using scanf
#include <stdio.h>
 
main()
{
   int number;
 
   printf("Enter an integer\n");
   scanf("%d",&number);
 
   printf("Integer entered by you is %d\n", number);
 
   return 0;
}
Output:
Enter a number
5
Number entered by you is 5
Example 3 - using if else control instructions
#include <stdio.h>
 
main()
{
   int x = 1;
 
   if ( x == 1 )
      printf("x is equal to one.\n");
   else
      printf("For comparison use == as = is the assignment operator.\n");
 
   return 0;
}
Output:
x is equal to one.
Example 4 - loop example
#include <stdio.h>
 
main()
{
   int value = 1;
 
   while(value<=3)
   {
      printf("Value is %d\n", value);
      value++;
   }
 
   return 0;
}
Output:
Value is 1
Value is 2
Value is 3
Example 5 - c program for prime number
#include <stdio.h>
 
main()
{
   int n, c;
 
   printf("Enter a number\n");
   scanf("%d", &n);
 
   if ( n == 2 )
      printf("Prime number.\n");
   else
   {
       for ( c = 2 ; c <= n - 1 ; c++ )
       {
           if ( n % c == 0 )
              break;
       }
       if ( c != n )
          printf("Not prime.\n");
       else
          printf("Prime number.\n");
   }
   return 0;
}
Example 6 - command line arguments
#include <stdio.h>
 
main(int argc, char *argv[])
{
   int c;
 
   printf("Number of command line arguments passed: %d\n", argc);
 
   for ( c = 0 ; c < argc ; c++)
      printf("%d. Command line argument passed is %s\n", c+1, argv[c]);
 
   return 0;
}
Above c program prints the number and all arguments which are passed to it.
Example 7 - Array program
#include <stdio.h>
 
main() 
{
    int array[100], n, c;
 
    printf("Enter the number of elements in array\n");
    scanf("%d", &n);
 
    printf("Enter %d elements\n", n);
 
    for ( c = 0 ; c < n ; c++ ) 
        scanf("%d", &array[c]);
 
    printf("Array elements entered by you are:\n");
 
    for ( c = 0 ; c < n ; c++ ) 
        printf("array[%d] = %d\n", c, array[c]);
 
    return 0;
}
Example 8 - function program
#include <stdio.h>
 
void my_function();
 
main()
{
   printf("Main function.\n");
 
   my_function();
 
   printf("Back in function main.\n");
 
   return 0;
}
 
void my_function()
{
   printf("Welcome to my function. Feel at home.\n");
}
Example 9 - Using comments in a program
#include <stdio.h>
 
main()
{
   // Single line comment in c source code
 
   printf("Writing comments is very useful.\n");
 
   /*
    * Multi line comment syntax
    * Comments help us to understand code later easily.
    * Will you write comments while developing programs ?
    */
 
   printf("Good luck c programmer.\n"); 
 
   return 0;
}

Example 10 - using structures in c programming
#include <stdio.h>
 
struct programming
{
    float constant;
    char *pointer;
};
 
main()
{
   struct programming variable;
   char string[] = "Programming in Software Development.";   
 
   variable.constant = 1.23;
   variable.pointer = string;
 
   printf("%f\n", variable.constant);
   printf("%s\n", variable.pointer);
 
   return 0;
}
Example 11 - c program for Fibonacci series
#include <stdio.h>
 
main()
{
   int n, first = 0, second = 1, next, c;
 
   printf("Enter the number of terms\n");
   scanf("%d",&n);
 
   printf("First %d terms of Fibonacci series are :-\n",n);
 
   for ( c = 0 ; c < n ; c++ )
   {
      if ( c <= 1 )
         next = c;
      else
      {
         next = first + second;
         first = second;
         second = next;
      }
      printf("%d\n",next);
   }
 
   return 0;
}
Example 12 - c graphics programming
#include <graphics.h>
#include <conio.h>
 
main()
{
    int gd = DETECT, gm;
 
    initgraph(&gd, &gm,"C:\\TC\\BGI");
 
    outtextxy(10,20, "Graphics source code example.");
 
    circle(200, 200, 50);
 
    setcolor(BLUE);
 
    line(350, 250, 450, 50);
 
    getch();
    closegraph( );
    return 0;
}